How to Solve Simultaneous Linear Equation Graphically

The graph of a linear equation ax+ by = c is a straight line equation.

Two distinct lines always intersect at exactly one point unless they are parallel (have the same slope).

The coordinates of the intersection point of the lines is the solution to the simultaneous linear equations describing the lines. So we would normally expect a pair of simultaneous equations to have just one solution.

Let's look at an example graphically:
2x + 3y = 7
4x + y = 9



From the graph we see that the point of intersection of the two lines is (2, 1)
Hence, the solution of the simultaneous equations is x = 2, y =1.

Example for complex conjugates

In grade 10 math , complex conjugates are a pair of complex numbers, both having the same real part, but with imaginary parts of opposite signs. For example, 3 + 4i and 3 - 4i are complex conjugates.
The conjugate of the complex number z

where a and b are real numbers, is

An alternate notation for the complex conjugate is z * . However, the notation avoids confusion with the notation for the conjugate transpose of a matrix, which can be thought of as a generalization of complex conjugation. If a complex number is represented as a 2×2 matrix, the notations are identical.We also can use scientific notation converter to find the number.

Let's an example problem from numeric and algebraic operations


Question:-

How do you use complex conjugates to find (3+7i)/(2-i) ?


Answer:-


In the Given problem the denominator is (2-i)

So ,it's conjugate is (2+i)

Multiplying both numerator and denominator with (2+i)

= (3+7i)(2+i)/(2-i)(2+i)

= (5+17i)/(4-i²)

We know that i² = -1

= (5+17i)/4+1

= (5+17i)/5 Answer

Problem on Order of Operations

In mathematics and computer programming, an expression or string of symbols is intended to represent a numerical value; a properly-formed expression may be evaluated in an unambiguous way. But in practice, an expression with multiple terms and operators may be written without parentheses, in which case the intended value of the expression is determined by convention. When a term in the expression is both preceded and followed by an operator such as minus or times, a convention is needed to clarify which operator should be applied first; this rule is known as a precedence rule, or more informally order of operation. From the earliest use of mathematical notation[citation needed], multiplication took precedence over addition, whichever side of a number it appeared on. Thus 3 + 4 × 5 = 5 × 4 + 3 = 23. When numeric and algebraic operations were first introduced, in the 16th and 17th centuries, exponents took precedence over both addition and multiplication, and could be placed only as a superscript to the right of their base. Thus 3 + 5 2 = 28 and 3 × 5 2 = 75. To change the order of operations calculator , a vinculum (an over line or underline) was originally used. Today one uses parentheses (). Thus, if one wants to force addition to precede multiplication, one writes (3 + 4) × 5 = 35.

Let's see an example from algebra answers

Question:-

solve 24-(24+4+2)+2 x (4 x 2)

by using PEMDAS rule

Answer:-

In PEMDAS

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

let's solve the given equation step by step
in the same order ...

24-(30)+2 x (16)

24-32+30

combine the same terms

24+32-30

56 - 30

26 is the answer.

Equation of the line which is passing through two points

Question :-

Find the equation of the line which is passing through two points (-3,7)(5,-1)

Answer:-

We have to use the point formula to find the equation of the line which is similar to midpoint formula

y-y1     x-x1
------ = ------
y2-y1     x2-x1

We have 2 points

( -3 , 7 )  and ( 5 , -1 )
  x1  y1          x2  y2

So the equation is

y-7      x-(-3)
------ = ------
-1-7      5-(-3)

y-7      x+3
------ = ------
-8        8

We can further simplify it by cross multiplication.that comes under indices maths

similarly we can find all points having an x-coordinate of 2 whose distance from the point 2 1 is 5

Simple quadratic equation

Topic: Quadratic Equation


An equation of the form ax²+bx+c=0 where a, b, c are real numbers and a =/ 0, is called a quadratic equation.

Question:

Solve: x2 - y = 3, x - y = -3

Answer:

   x2 - y = 3, x - y = -3

   x2 - y = 3

    x  - y = -3

    + y + y
    __________
    x = y - 3

  Putting this in the first equation

  (y -3)x2 - y = 3

 y2 - 6x + 9 - = 3

 y2 - 6x + 9 - y = 3

 y2 - 7y + 9 = 3

        -3    -3
        ____________

Factoring (y - 6) (y -1) = 0

         y = 6 on 1

         x = y - 3 = 6 - 3 = 3

         x = 1 - 3 = - 2

  The solution set is : {(-2,1) , (3,6)}

Graphing trigonometric functions

Graphs are useful for analyzing properties of various trigonometric functions and are valuable in many applications.The most common use of these functions is in analyzing waves ,sound and electric current and voltage.Although any trig function can be graphed,the emphasis here is on graphing trigonometric functions.

Graphing a Sine function

The graph of y= sinx(where x equals the angle) can be sketched by simply constructing a table ,like the one shown below,selecting values for the angle,x and solve for y,then plotting the points on a graph .

x(2)    : -90   45    0    45      90   180   270   360 

y(sin2) : -1   -0.8   0   0.707     1     0    -1     0

The result graph below,which continues indefinitely in both directions

Note:- The x-axis is set in increments of standard angles in degrees,although radians can also be used .
The y- axis is set in decimal increments ,equal to function values of the corresponding angles.

For more help on this, you can reply me.

Maximum and Minimum value of a function

Maximum and minimum value of a function can be determined by simplifying the function with given intervals of time.

Function is a concept which expresses the idea that one quantity completely determines another quantity. Here is one such problem for your practice and understand how the value of function varies with respect to given interval of time.

Question : Find the maximum and minimum value of the function y = x³ - x on the interval [-3,3]

On substituting the value of x as -3 and 3, maxima and minima of function are found.

Solution :

When x = -3

y = x³ - x

= (-3)³ - (-3)

= -27 + 3

= - 24

And when x = 3

y = (3)³ - 3

= 27 - 3

= 24

Hence maximum value of function is 24 and minimum is - 24