pre algebra homework

Hi Friends!!!

Can any tell me why homework given to students? Why pre algebra homework is given to students?

Schoolwork, or preparation assignment, refers to tasks assigned to students by their teachers to be realized mostly extracurricular of people, and derives its call from the fact that most students do the age of such transmute at institution. Democratic school work assignments may include a amount or period of representation to be performed, writing or typing to be complete, problems to be resolved, a polish projection to be stacked or added skills to be experienced.

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free math problems

Simplify the expression: -10x - 7y - 8x + 9y + 6x + 4z
Solution:
-10x - 7y - 8x + 9y + 6x + 4z
Add the like terms in the given expression
(-10 - 8 + 6) x + (-7 + 9) y + 4z
Simplify the expression
-12 x + 2y + 4z
So, the answer is -12 x + 2y + 4z.
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algebra helper

Hi Friends!!!

Looking for algebra helper? Well, you have come to the right place! MATH-TEACHER makes the teaching and learning of math as simple as math can get! Arithmetic builds progressively from idea to idea. MATH-TEACHER helps students understand each idea before moving on to the next. Each lesson first presents the ideas and a boundless number of sample issues.

Free online algebra tutoring provides Flexibility in solving Issues. Students can pick their own solving route and are not confused by the limited acceptable exposés used by our competitors. Guidance provided on how to start each issue if needed. Smart Hints catch common errors .Difficulty adjusts to the student's competence

Look for some free online algebra tutor and practice from them. There are plenty of sites which they find online and they help us a lot in solving the arithmetic issues. In the event you practice these issues you will solve math word issues within a few seconds.

factoring expressions

Let us learn about factoring expressions

In mathematics, Polynomial expression is one important topic in algebra. Factoring polynomial expression is defined as the process of solving the given polynomials expression by using the concepts of factoring. Using the greatest common factor, the given polynomial expression can be factorized. Let us solve some example problems for factoring polynomial expression.

Factoring Polynomial Expression Steps:

Different steps to solve polynomials expression,

• Given polynomial expression
• Polynomial expression is arranged in the order of powers and then it is in the standard form of ax² + bx + c = 0
• Factor the polynomial expression

• Simplify the factored terms

In our next blog we shall learn about atomic radius periodic table I hope the above explanation was useful.Keep reading and leave your

volume of a cube formula

Let us learn about volume of a cube formula

Cube is one of the basic three dimensional images. Cube consists of six faces and each face meets at right angles. In total, cube has eight vertices's and twelve edges. As cube consists of six faces, it is also known as regular hexahedron. Volume is to be calculated for three dimensional images. Volume cube calculator is used to calculate the volume of cube in online. This calculator is very helpful for calculating the volume of cube. When the required values are entered in the calculator, it automatically generates the output.

Formula 1:

The formula for calculating the volume of a cube if all the sides are equal,
Volume of a cube = a³
Where, “a” is the side of the cube.
Formula 2:
Formula for calculating the volume of cube, when all the sides are different,
Volume of cube = l*w*h
where, l = length
w = width and
h = height

In our next blog we shall learn about unit step function I hope the above explanation was useful.Keep reading and leave your

pythagoras theorem proof

Let us learn about pythagoras theorem proof


In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).
It can be expressed in equation form as,
a² + b² = c²
Where, a and b are the sides of a right triangle
c is the hypotenuse of the right triangle

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orthographic drawing

Let us learn about orthographic drawing

A projection on a plane, using lines perpendicular to the plane

Graphic communications has many forms. Orthographics is one such form. It was developed as a way of communicating information about physical objects. It is part of a universal system of drawings. House plans - one well known drawing format, are a form of othographic projection. In simple terms, orthographic drawings are views (front, side, top, and so on) of an object. An orthographic view is only one side. It takes several views to show all the object. Before getting to views, it is useful to look at another type of drawing. Pictorial drawings show several sides at the same time. Many people find pictorial drawings easier to understand. They do not provide as much information as orthographic views. The most commonly used pictorial drawing for technical information is called isometric drawings. Isometric drawings were developed to approximate perspective, but are much easier to draw. For a square box, all the sides are drawn as vertical lines, or at 30 degrees to the horizontal.

Match the orthographic drawing to the isometric drawing.

A ) Figure 4
B ) Figure 2
C ) Figure 3
D ) Figure 1

Steps to derive

1 An orthographic drawing shows the top view, front view and right-side view of a three-dimensional figure.
2 Develop a three-dimensional figure from the orthographic views.
3 Top view forms the base of the structure. A three-dimensional structure is developed from the orthographic views.
4 Figure 2 gives the isometric drawing of the structure developed from orthographic drawing.

Hence the right answer is Option B

In our next blog we shall learn about "alphabet of lines"

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least squares regression line

Let us learn about least squares regression line

Regression is the measure of the average relationship between two or more variables in terms of the original units of the data. This can be represented by an equation of a straight line which can be obtained by the method of least squares. The equations are of two forms as y on x and x on y. To obtain them we use the following normal equatons.

(i) Regression line y on x: It is given by y = hx + k.

Their normal equations are:

Σy = hΣx + nk ……………… (1)

Σxy = hΣx ² + kΣx …………. (2)

By solving (1) and (2), we arrive at the required equation y = hx + k

(ii) Regression line x on y: It is given by x = hy + k.

Their normal equations are:

Σx = hΣy + nk ……….. (1)

Σxy = hΣy ² + kΣy ………… (2)

By solving (1) and (2), we arrive at the required equations x = hy + k

In our next blog we shall learn about converting 1 meter in feet

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