An ordinary differential equation is an differential equation in For instance (i)dy/dx = x + 5 (ii) (y′)2 + (y′)3 + 3y = x2 which is a single independent variable enters either explicitly or implicitly are all ordinary non linear differential equations And now we see about the non linear differential equations.
Non linear differential equations in First order
Order and degree of a non linear differential equations:
Definition of non linear differential equations :
The order of an differential equation is the order of the highest order derivative occurring in it. The degree of the differential equation is the highest order derivative which occurs in it, after the differential equation has been made free from radicals and fractions as far as the derivatives are concerned.The degree of a non linear differential equation does not require variables like r, s, t … to be free from radicals and fractions.
Find the order and degree of the following differential equations:
ii) y = 4dy/dx + 3xdx/dy
y = 4dy/dx + 3xdx/dy y = 4(dy/dx) + 3x 1/(dy/dx )
Making the above equation free from fractions involving
dy/dx we get y .dy/dx = 4(dy/dx)2 + 3x 2Highest order = 1
Degree of Highest order = 2
(order, degree) = (1, 2)
Problem for non linear differential equations:
Formation of non linear differential equations :
Form the differential equation from the following equations.
y = e2x (A + Bx)
ye−2x = A+ Bx … (1)
Since the above equation contains two arbitrary constants, differentiating
twice, we get y′e−2x − 2y e−2x = B
{y′′e−2x − 2y′ e−2x} − 2{y′e−2x − 2y e−2x} = 0
e−2x {y′′ − 4y′ + 4y} = 0 [‡ e−2x ≠ 0]
y′′ − 4y′ + 4y = 0 is the differential equation.
Non linear Differential equations of first order and also first degree :
Solve: 3ex tan y dx + (1 + ex) sec2y dy = 0
`=>` 3 log (1 + ex) + log tan y = log c
`=>` log [tan y (1 + ex)3] = log c
`=>` (1 + ex)3
required solution to the problem is tan y = c