The definite integral f(x) between the limits x=a and x=b is defined by
int_a^bf(x)dx and its value is F(b) - F(a).
Here a is called the lower limit and b is the the upper limit of the integral, and F(x) is integral of f(x).The value fo the definite integral is obtained by finding out the indefinite integral first and then substituting the upper limit and lower limit for the variable in the indefinite integral.
Please express your views of this topic Evaluate the Definite Integral by commenting on blog.
Properties of Definite Integral for evaluating definite integrals
Let int f(x)dx =F(x) + c.
Then int_a^bf(x)dx = F(b) - F(a) = [F(x)]a to b
Property1.
int_a^bf(x)dx =int_a^bf(t)dt
Proof:
int_a^bf(x)dx = [F(x)]a to b = F(b) - F(a).
int_a^bf(t)dt = [F(t)]a to b = F(b) - F(a).
Therefore
int_a^bf(x)dx = int_a^bf(t)dt
Property:2
int_a^bf(x)dx = - int_b^af(x)dx
Proof:
= - int_b^af(x)dx = - [F(x)] b to a
=-[F(a) - F(b)]
=F[b]-F[a].
=int_a^bf(x)dx
Property 3:
int_a^bf(x)dx = int_a^cf(x)dx + int_c^bf(x)dx
Proof:
= int_a^cf(x)dx +int_a^bf(x)dx
=[f()x]a to c + [F(x)]c to b
=F(c) - F(a) + F(b) - F(c).
=F(b) - F(a).
Property 4:
int_a^0f(x)dx = int_0^af(a - x)dx
put a-x=t
dx=-dt
When x=0, t=a, when x=a, t=0.
=- int_a^0f(x)dx
= int_0^af(t)dt
int_0^af(t)dt
int_0^af(x)dx
=int_0^af(a-x)dx.
Using Trignonmentry Problem
Evaluate: int_0^(pi/2)sin2xdx
Solution:
Let I = int_0^(pi/2)sin2xdx
= int_0^(pi/2)sin2[(pi/2)-x]dx
int_0^(pi/2)cos2xdx
Here First I, and Second I
Adding (1) and (2)
we get 2I=int_0^(pi/2)(sint2x+cos2x)dx
=int_0^(pi/2)dx
=[x] 0 to pi The value for x will be assing as 0 and pi
=(pi /2). The value of pi assume as 180.
2I = (pi/2 )
I=(pi /4). Answer
I am planning to write more post on factoring degree 3 polynomials and cbse sample papers for class 9 sa2. Keep checking my blog.
Evaluate:
int_0^(pi/2)log (tan x)dx
int_0^(pi/2)log (tan x)dx
int_0^(pi/2)log (tan x)dx
int_0^(pi/2)log (tan(pi/2)- x)dx
= int_0^(pi/2)log (cot x)dx
= Adding both First and Second Equations We get
int_0^(pi/2)[log (tan x +log (cot x))]dx
= int_0^(pi/2)log(tan x cot x)
= int_0^(pi/2)log 1dx
=0
I=0.
Reduction formulae:
A formula which expresses the integral of the nth indexed function interms of that of (n-1) th indexed (or lower). the function is called reduction formulae
No comments:
Post a Comment